Tuesday, June 23, 2009

Circuit Analysis II Lecture 5

Disclaimer: This series of posts is to serve as notes for myself as well as any others interested in the subject of Circuit Analysis II. This is the course ECE 213 at UNM.
The course will follow the book:
Electric Circuits (8th Edition)

The links on the right, will contain all the links to this course's lecture notes.

AP 12.3 page 485

F(s) = (6s2 + 26s +26)/(s+1)(s+2)(s+3)

using Partial fraction decomposition we get
K1 = 3
K2 = 2
K3 = 1

Of course converting back to the time domain we get
(3e-t + 2e-2t + e-3t)u(t)

Next we do Problem 13.5 from page 519
Our plan is to move to the s-domain, analyze the circuit and then move back to the time domain (or t-domain)

The circuit in the s-domain has the values as such:
5/s for the current
15/s for the voltage
1/s for the capacitor
s for the inductor

Additionally to note is that we have no initial charge so we don't need to "convert" the inductor to a inductor current/voltage source combination, as well as the capacitor.

So using Nodal Analysis we get:
Node 1:
-5/s + v1/1/s + v1 - v2/s = 0

Node 2:
v2 - v1/s + v2/3 + v2 - 15/s / 15 = 0

We were asked to solve for v1 and v2

we were given that it ends up as :
s(s+3) / s(s+.5)(s+2)

Using Partial Fraction Decomposition:
We were asked to solve for all the k's.

Once we finish, convert it to t-domain.

We were then asked to try it using mesh current.

Hw: Try 13.42, and Ap 13.8c using node voltage

Review Thevinin, Norton Equivalent for next class.

We then went over the test, as well as did all the problems.
I have problem 7 solved, and 8 solved, from class, the rest of the problems can be given if you just either leave a comment or email me.

Continue on to Lecture 6 6/23/09